3.12.3.4
Length contraction and the muon lifetime experiment
Turning Points in Physics | AQA A-Level Physics
Key Definitions
Length contraction: An object moving relative to an observer appears shorter in the direction of motion than its proper length.
Proper length ($L_0$): The length of an object measured in the frame where the object is at rest. It is always the longest measured length.
Proper length ($L_0$): The length of an object measured in the frame where the object is at rest. It is always the longest measured length.
The equation
$$L = \frac{L_0}{\gamma} = L_0 \sqrt{1 - \frac{v^2}{c^2}}$$
- $L$ is the contracted length measured by the observer who sees the object moving.
- $L_0$ is the proper length measured in the object's rest frame.
- Since $\gamma \geq 1$, the contracted length $L$ is always less than or equal to the proper length $L_0$.
- Contraction only occurs in the direction of motion. Dimensions perpendicular to the motion are unchanged.
The muon experiment from the muon's perspective
- In the Earth's frame, muon survival is explained by time dilation (the muon's clock runs slowly, so it lives long enough to reach the ground).
- In the muon's rest frame, the muon's lifetime is unchanged at 1.6 microseconds. Instead, the distance from the top of the atmosphere to the ground is contracted.
- With $\gamma \approx 5$, the 10 km height contracts to about 2 km in the muon's frame. At $0.98c$, the muon can cover 2 km in its short lifetime.
- Crucially, both explanations (time dilation from Earth's frame, length contraction from muon's frame) give the same physical prediction: muons reach the ground. This is a requirement of the first postulate, that the laws of physics are the same in both frames.
Derivation from the Lorentz transformation
- Length contraction follows from time dilation using $\text{speed} = \text{distance}/\text{time}$.
- In the rest frame: $v = L_0 / \Delta t$. In the moving frame: $v = L / \Delta t_0$.
- Since $v$ is the same in both frames and $\Delta t = \gamma \Delta t_0$, we get $L_0 / (\gamma \Delta t_0) = L / \Delta t_0$, giving $L = L_0 / \gamma$.
Common Mistake
Students sometimes multiply by $\gamma$ for length contraction (as for time dilation). Remember: time dilation multiplies by $\gamma$ ($\Delta t = \gamma \Delta t_0$) but length contraction divides by $\gamma$ ($L = L_0 / \gamma$). Moving clocks run slow (times get longer); moving rulers get short (lengths get shorter).