3.4.1.1

Resolving a vector splits it into two perpendicular components

Scalars & Vectors — AQA A-Level Physics

$$F_x = F \cos \theta$$
  • $F_x$: horizontal component
  • $F$: magnitude of the vector
  • $θ$: angle between the vector and the horizontal
$$F_y = F \sin \theta$$
  • $F_y$: vertical component
  • $F$: magnitude of the vector
  • $θ$: angle between the vector and the horizontal
Worked Example
A helicopter provides a lift of 250 kN when the blades are tilted at 15 degrees from the vertical. Calculate the horizontal and vertical components of the lift force.
Show Solution
1
Identify the angle

The force is 15 degrees from the vertical, so the vertical component uses cos and the horizontal uses sin.

2
Calculate the vertical component

$$F_V = 250 \times \cos 15° = 242 \text{ kN}$$

3
Calculate the horizontal component

$$F_H = 250 \times \sin 15° = 64.7 \text{ kN}$$

Answer
$Vertical = 242 kN, Horizontal = 64.7 kN.$
Common Mistake MEDIUM
Students often: Swapping sin and cos when resolving vectors.
Instead: The cos component is always the one adjacent to the angle (the 'cos sandwich'). If the angle is from the horizontal, the horizontal component is F cos(theta). If the angle is from the vertical, the vertical component is F cos(theta).
Scalars & Vectors Overview