3.8.1.4

Gamma emission releases energy without changing the nucleus composition

Nuclear Structure & Radiation — AQA A-Level Physics

Worked Example
Molybdenum-99 undergoes beta-minus decay to form metastable technetium-99m, which then emits gamma radiation to reach the ground stateThe lowest energy level of an atom. The state in which all electrons are in their lowest possible energy levels.. Write both decay equations.
Show Solution
1
Write the beta-minus decay of Mo-99

$${}^{99}_{42}\text{Mo} \rightarrow {}^{99\text{m}}_{43}\text{Tc} + {}^{0}_{-1}\beta + \bar{\nu}_e$$

2
Write the gamma emission from Tc-99m
$${}^{99\text{m}}_{43}\text{Tc} \rightarrow {}^{99}_{43}\text{Tc} + \gamma$$

The 'm' denotes the metastable excited state. Half-lifeThe time taken for half the number of radioactive nuclei in a sample to decay, or for the activityThe number of nuclear decays per unit time. Measured in becquerels (Bq), where 1 Bq = 1 decay per second. to halve. of Tc-99m is 6 hours.

Answer
Mo-99 → Tc-99m + β⁻ + ν̄ₑ, then Tc-99m → Tc-99 + γ
Nuclear Structure & Radiation Overview