3.11.1.6
Angular Momentum
Engineering Physics | AQA A-Level Physics
Key Definition
Angular momentum ($L$): The rotational equivalent of linear momentum. Defined as the product of the moment of inertia and the angular velocity. Measured in kg m$^2$ rad s$^{-1}$.
Angular momentum
- Linear momentum is defined as $p = mv$. Angular momentum is the rotational equivalent: $$L = I\omega$$
- Where: $L$ = angular momentum (kg m$^2$ rad s$^{-1}$), $I$ = moment of inertia (kg m$^2$), $\omega$ = angular velocity (rad s$^{-1}$).
Angular momentum of a point mass
- For a point mass $m$ at distance $r$ from the axis, with $I = mr^2$ and $\omega = \frac{v}{r}$: $$L = I\omega = (mr^2) \times \frac{v}{r} = mvr$$
- This is useful when dealing with particles moving in straight lines that have angular momentum about an external axis.
Conservation of angular momentum
- As with linear momentum, angular momentum is always conserved.
- The principle states: the angular momentum of a system always remains constant, unless a net torque is acting on the system.
- This conservation law has many real-world applications:
- A person on a spinning chair spins faster when they pull their arms in and slower when they extend them.
- Objects in elliptical orbits travel faster nearer the body they orbit and slower when further away.
- Ice skaters change their rotational velocity by extending or contracting their arms.
- Tornadoes spin faster as their radius decreases.
- Problems involving a change in angular momentum use: $$I_i\omega_i = I_f\omega_f$$
Worked example: exploding star
- A spherical star of mass $M$ and radius $R$ rotates about its axis. It explodes, leaving a remnant with mass $\frac{M}{10}$ and radius $\frac{R}{50}$. The moment of inertia of a sphere is $I = \frac{2}{5}MR^2$.
- Applying conservation of angular momentum: $$\left(\frac{2}{5}MR^2\right)\omega_i = \left(\frac{2}{5} \times \frac{M}{10} \times \left(\frac{R}{50}\right)^2\right)\omega_f$$
- Simplifying: $\frac{\omega_f}{\omega_i} = 25\,000$
- The remnant star spins 25,000 times faster than the original.
Common Mistake
Objects travelling in straight lines can have angular momentum relative to an axis. If the particle's line of motion does not pass through the axis, it has angular momentum $L = mvr$ about that axis. If it hits the axis directly, it causes no rotation and has zero angular momentum about that point.