3.11.1.3
Torque
Engineering Physics | AQA A-Level Physics
Key Definition
Torque ($\tau$): The change in rotational motion due to a turning force. Calculated as the product of the applied force and the perpendicular distance from the axis of rotation. Measured in N m.
Torque of a single force
- The torque of a force $F$ about an axis is given by: $$\tau = Fr$$
- Where: $\tau$ = torque (N m), $F$ = applied force (N), $r$ = perpendicular distance between the axis of rotation and the line of action of the force (m).
- Think of a cyclist pushing down on a pedal. The torque on the chain ring depends on the magnitude of the force and the length of the crank arm.
Torque of a couple
- When two equal and opposite forces act at different points on an object, this is called a coupleA pair of equal and opposite forces whose lines of action do not coincide. A couple produces rotation without any linear acceleration..
- The torque of a couple is the sum of the moments produced by each of the forces. For a steering wheel of radius $r$: $$\tau = (F \times r) + (F \times r) = 2Fr$$
- Crucially, the forces are equal and opposite, so the resultant force is zero. This means the object rotates but does not accelerate linearly.
- Due to Newton's Second Law ($F = ma$), a steering wheel under a couple rotates with constant angular speed but remains in the same location.
Worked example: grinding wheel
- A grinding wheel has a diameter of 0.13 m. A tangential force of 12.0 N acts on the edge.
- The radius is $r = \frac{0.13}{2} = 0.065$ m.
- Therefore: $\tau = Fr = 12.0 \times 0.065 = 0.78$ N m.
Common Mistake
The terminology in this section can be confusing. A moment is not a "turning force": the turning force is only part of it. The moment is the effect that the turning force has on the system when applied at a distance from a turning point. When calculating torque, always identify the magnitude of the applied force and the perpendicular distance to the axis of rotation.