3.9.3.4
Hubble's law relates a galaxy's recession speed to its distance, and gives us the age of the Universe
Astrophysics | AQA A-Level Physics
Key Definition
Hubble's law: The recessional velocity of a galaxy is proportional to its distance from Earth. Expressed mathematically as $v = Hd$.
The equation
$$v = Hd$$- $v$ = recessional velocity of the galaxy (km s$^{-1}$)
- $H$ = the Hubble constant (km s$^{-1}$ Mpc$^{-1}$)
- $d$ = distance from the Earth to the galaxy (Mpc)
- Hubble's law tells us that the further away a galaxy is, the faster it is moving away from us. Closer galaxies recede more slowly.
- A graph of recession velocity ($v$) against distance ($d$) gives a straight line through the origin. The gradient of this line is the Hubble constant $H$.
The Hubble constant
- The Hubble constant $H$ is the constant of proportionality in Hubble's law:
- Its value has been estimated using data from thousands of galaxies and standard candles.
- The current best estimate, based on CMB observations by the Planck satellite, is approximately:
- This value is constantly under review as more data is collected.
Estimating the age of the Universe
- Hubble's law can give us an estimate of the age of the Universe. The key part is the reasoning:
- If all matter was at the same point at the start of the Big Bang ($t = 0$), then a galaxy now at distance $d$, moving at speed $v$, has been travelling for time $t = d / v$.
- Since $v = Hd$, we can substitute to get:
- This assumes that the recessional speed has been constant throughout the history of the Universe.
- Using the current estimate of $H \approx 67.4$ km s$^{-1}$ Mpc$^{-1}$, converting to SI units and taking the reciprocal gives an age of approximately 14.6 billion years.
Common Mistake
Unit conversions in Hubble constant calculations catch many students out. To find $1/H$ in seconds, you must first convert $H$ from km s$^{-1}$ Mpc$^{-1}$ to s$^{-1}$. That means converting km to m (multiply by 1000) and Mpc to m (1 pc = $3.1 \times 10^{16}$ m, so 1 Mpc = $3.1 \times 10^{22}$ m). Only then can you take the reciprocal to get a time in seconds.